(4c-9)(c^2+c-7)=0

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Solution for (4c-9)(c^2+c-7)=0 equation:


Simplifying
(4c + -9)(c2 + c + -7) = 0

Reorder the terms:
(-9 + 4c)(c2 + c + -7) = 0

Reorder the terms:
(-9 + 4c)(-7 + c + c2) = 0

Multiply (-9 + 4c) * (-7 + c + c2)
(-9(-7 + c + c2) + 4c * (-7 + c + c2)) = 0
((-7 * -9 + c * -9 + c2 * -9) + 4c * (-7 + c + c2)) = 0
((63 + -9c + -9c2) + 4c * (-7 + c + c2)) = 0
(63 + -9c + -9c2 + (-7 * 4c + c * 4c + c2 * 4c)) = 0
(63 + -9c + -9c2 + (-28c + 4c2 + 4c3)) = 0

Reorder the terms:
(63 + -9c + -28c + -9c2 + 4c2 + 4c3) = 0

Combine like terms: -9c + -28c = -37c
(63 + -37c + -9c2 + 4c2 + 4c3) = 0

Combine like terms: -9c2 + 4c2 = -5c2
(63 + -37c + -5c2 + 4c3) = 0

Solving
63 + -37c + -5c2 + 4c3 = 0

Solving for variable 'c'.

The solution to this equation could not be determined.

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